(7y+28)(y^2+5y+4)=0

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Solution for (7y+28)(y^2+5y+4)=0 equation:


Simplifying
(7y + 28)(y2 + 5y + 4) = 0

Reorder the terms:
(28 + 7y)(y2 + 5y + 4) = 0

Reorder the terms:
(28 + 7y)(4 + 5y + y2) = 0

Multiply (28 + 7y) * (4 + 5y + y2)
(28(4 + 5y + y2) + 7y * (4 + 5y + y2)) = 0
((4 * 28 + 5y * 28 + y2 * 28) + 7y * (4 + 5y + y2)) = 0
((112 + 140y + 28y2) + 7y * (4 + 5y + y2)) = 0
(112 + 140y + 28y2 + (4 * 7y + 5y * 7y + y2 * 7y)) = 0
(112 + 140y + 28y2 + (28y + 35y2 + 7y3)) = 0

Reorder the terms:
(112 + 140y + 28y + 28y2 + 35y2 + 7y3) = 0

Combine like terms: 140y + 28y = 168y
(112 + 168y + 28y2 + 35y2 + 7y3) = 0

Combine like terms: 28y2 + 35y2 = 63y2
(112 + 168y + 63y2 + 7y3) = 0

Solving
112 + 168y + 63y2 + 7y3 = 0

Solving for variable 'y'.

Factor out the Greatest Common Factor (GCF), '7'.
7(16 + 24y + 9y2 + y3) = 0

Ignore the factor 7.

Subproblem 1

Set the factor '(16 + 24y + 9y2 + y3)' equal to zero and attempt to solve: Simplifying 16 + 24y + 9y2 + y3 = 0 Solving 16 + 24y + 9y2 + y3 = 0 The solution to this equation could not be determined. This subproblem is being ignored because a solution could not be determined. The solution to this equation could not be determined.

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